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November 23, 2014

November 23, 2014

Posted by **soasi piutau** on Monday, May 7, 2012 at 8:41am.

a) lim x->-2 (x^2 -9)/(x^2+x-2)

b) lim x -> -∞ √(ax^2+bx+c)/dx + e, where a > 0, b,c,d, and e are constant.

- calculus -
**Steve**, Monday, May 7, 2012 at 9:56ama)

since you have (x-3)(x+3) / (x-1)(x+2) the numerator is nonzero when x = -2, the limit will be ∞, depending on the direction of approach,

b)

I assume you meant √(ax^2+bx+c)/(dx+e) since otherwise it is boring. Divide top and bottom by x to get

√(a+b/x+c/x^2)/(d+e/x) = √a/d

however, the numerator is positive and the denominator is negative as x -> -∞, so we really end up with -√a/d

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