What is the molarity of a solution containing 9.0 moles of solute in 2500 mL of solution?
I got this answer: M = (9.0mols/2.5L)= 3.6M
Is this correct?
Thanks
very good.
Thank you DrBob222 for your help!
Yes, your calculation is correct. To find the molarity (M) of a solution, you divide the number of moles of solute by the volume of the solution in liters. In this case, you have 9.0 moles of solute and a solution volume of 2500 mL, which is equivalent to 2.5 L. Therefore, the molarity of the solution is 3.6 M.
Yes, your answer is correct! To solve for the molarity (M) of a solution, you divide the number of moles of solute by the volume of the solution in liters. In this case, you have 9.0 moles of solute and 2500 mL of solution.
First, it is important to convert the volume from milliliters to liters. There are 1000 mL in a liter, so dividing 2500 mL by 1000 gives you 2.5 L.
Next, divide the number of moles of solute (9.0 moles) by the volume of the solution (2.5 L) to get the molarity:
M = 9.0 moles / 2.5 L = 3.6 M
Therefore, the molarity of the solution is 3.6 M.