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April 2, 2015

April 2, 2015

Posted by **Anonymous** on Sunday, May 6, 2012 at 9:15pm.

Please help, I don't know how to do this problem.

- chemistry -
**DrBob222**, Sunday, May 6, 2012 at 10:25pmHere is how you do this with a little chicanery. First, we assume the reaction goes to completion to the right. That's not a bad assumption considering the size of the formation constant.

.........Co^2+ + 4NH3 ==> Co(NH3)4^2+

Initial.0.140....1.2........0

change...-0.140.-4*1.2.....0.140

equil.....0.......0.64......0.140

Actually, this isn't at equilibrium since we drove it to completion. Therefore, the numbers above are a little TOO far for equilibrium; therefore, it must move back to the left. How much will it move? We set up another set of conditions but start with where we ended above.

..........Co^2+ + 4NH3 ==> Co(NH3)4^2+

I.........0.......0.64......0.140

C.........+x......+4x.......-x

E.........x.....0.64+4x.....-x

Substitute into K.

K = [Co(NH3)4^2+]/[Co^2+][MH3]^4

5E31 = [0.140-x][x][0.64+4x]^4

Now assume 0.140-x = 0.140 and assume 0.64+4x = 0.64 and solve for x = (Co^2+). It's a very small number.

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