Posted by help please on Sunday, May 6, 2012 at 8:45pm.
m1=2 kg, v = 10 m/s, m2 = 3 kg, α =30º, u2 = 4 m/s. β=? u1=?
Take the x axis to be the original direction of motion of 2-kg ball. The equations expressing the conservation of momentum for the components in the x and y directions are
p(x): m1•v = m1•u1•cos α + m2•u2•cos β,
p(y): 0 = m1•u1•sin α - m2•u2•sin β.
cos β = (m1•v - m1•u1•cos α)/ m2•u2,
sin β = m1•u1•sin α/ m2•u2,
sin β/ cos β = tan β =
= m1•u1•sin α/ m1•v(1-cos α) =
=sin α/(1-cos α) = 0.5/(1-0.866) = 3.73,
α = arctan 3.73 = 75º.
u1 = m2•u2•sin β / m1•sin α =
= 3•4•sin75º/2•sin30º = 11.6 m/s.
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