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July 28, 2014

July 28, 2014

Posted by **Bob** on Sunday, May 6, 2012 at 8:13pm.

- Physics 121 -
**Elena**, Monday, May 7, 2012 at 8:39amm1 =4 kg, m2 = 2 kg, m = 0.5 kg, R = 0.25 m, h= 0.75 m.

Projections on the horizontal and vertical axis:

m1•a = T1

m2•a =m2•g-T2,

I•ε =M.

If the pulley is the disk (cylinder) I =m•R²/2 ,

M = torque = (T1-T2) •R,

ε = a/R,

I•ε =M => m•R²•a/2•R =(T1-T2) •R =>

m•a/2 = (T1-T2).

m1•a + m2•a = T1 + m2•g -T2 = m2•g + (T1-T2) = m2•g +m•a/2,

a = m2•a/[m1+m2-m(m/2)] = 2•9.8/(4+2+0.125)=3.336 m/s^2,

a = v^2/2•h ,

v=sqrt(2•a•h) = sqrt(2•3.336•0.75) = 2.2 m/s^2

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