Posted by **emma** on Sunday, May 6, 2012 at 4:54am.

A box weighing 65.0 N rests on a table. A rope tied to the box runs vertically upward over a pulley and a weight is hung from the other end.

Part a) Determine the force that the table exerts on the box if the weight hanging on the other side of the pulley weighs 24.0 N .

Part b) Determine the force that the table exerts on the box if the weight hanging on the other side of the pulley weighs 43.0 N .

part c)Determine the force that the table exerts on the box if the weight hanging on the other side of the pulley weighs 82.0 N .

- physics- please help ! -
**Elena**, Sunday, May 6, 2012 at 5:19am
m•g = 65 N, m1•g =24 N, m2•g =23 N, m3•g =82 N

Tthe force that the table exerts on the box is the normal reaction

(a) N =m•g –T1 = m•g –m1•g =

= 65 – 24 = 41 N,

(b) N =m•g –T2 = m•g –m2•g =

= 65 – 43 = 22 N,

(c) N =0.

The box is moving at the acceleration

a = g•(m3-m)/(m3+m)

- physics- please help ! -
**tiffany**, Friday, October 19, 2012 at 11:23am
this is 13

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