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posted by saya Sunday, May 6, 2012 at 1:30am.
solve. check for extraneous roots.3^2x-4(3)^x+3=0
let y = 3^x , then your equation becomes y^2 - 4y + 3 = 0 (y-3)(y-1) = 0 y = 3 or y = 1 then 3^x = 3 ---> x = 1 3^x = 1 ---> x = 0
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