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July 30, 2014

July 30, 2014

Posted by **saya** on Sunday, May 6, 2012 at 1:29am.

- math12 -
**Reiny**, Sunday, May 6, 2012 at 7:37amtake log of both sides

log(5^(p+4)) = log(2^(4-5p))

(p+4)log5 = (4-5p)log2

p log5 + 4log5 = 4log2 - 5p log2

p(log5 + 5log2) = 4log2 - 4log5

p = (4log2 - 4log5)/( log5 + 5log2) = appr -.72

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