Posted by nicole on Saturday, May 5, 2012 at 6:01pm.
pH = -log(H^+)
pOH = -log(OH^-)
pH + pOH = pKw = 14 and
(H^+)(OH^-) = Kw.
One or more of the four above will calculate all you ever need to know abouat H^+), (OH^-), pH and pOH.
THANK YOU :)
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