Wednesday
October 1, 2014

Homework Help: CALCULUS

Posted by Anonymous on Saturday, May 5, 2012 at 5:08pm.

The region R is a rectangle with vertices P(a,lna), Q(a,0), S(3,0), and T(3,lna), where 1<a<3.
I found that the expression for the area of the rectangle is f(a) = (ln(a))(3-a).
The area of the rectangle is maximized for some c beween 1 and 3. Write the expression you would need to solve in order to find c.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Calculus - The region R is a rectangle with vertices P(a,lna), Q(a,0), S(3,0), ...
Math - ln - Find ln(1/(√(ab^3)) of lna = 2 and lnb = 3. = ln1 - ln(ab)^(3/...
9th grade polynomials - How do you write the expression for the area of the ...
Math - If the length of a rectangle is (2x-1)cm and its width is (x+3)cm. How do...
calculus - A rectangle has its base on the x-axis and its upper two vertices on ...
Calculus - Hello, could someone please help me with this problem? I'm a little ...
Calculus - integration - Q. (15^x/3^x) dx i know that the (a^x) dx = a^x/lna...
math - The leng of the smaller rectangle is 1 inch less than twice its wide. ...
Calculus - A rectangle is constructed with its base on the diameter of a ...
calculus - A rectangle is constructed with its base on the diameter of a ...

Search
Members