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September 2, 2014

September 2, 2014

Posted by **Liz** on Saturday, May 5, 2012 at 2:03pm.

- Calculus -
**MathMate**, Saturday, May 5, 2012 at 8:09pmStrength, S = xy²

But we know that

x²+y²≤(3/2)²

therefore, substitute

S(x)=x((3/2)²-x²)

For maximum strength,

dS(x)/dx = 9/4-3*x^2 =0

=>

x²=3/4

x=sqrt(3/4)

y^2=(3/2)^2-x^2=9/4-3/4=6/4

y=sqrt(1.5)

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