Posted by **Lucy** on Saturday, May 5, 2012 at 6:51am.

Divide

(42b^3 + 23b^2 + 38b + 49)/(6b + 5)

This is tricky..help?

## Answer This Question

## Related Questions

- Algebra - Divide (42b^3 + 23b^2 + 38b + 49)/ (6b + 5)
- algebra ll - Divide (42b^3 + 23b^2 + 38b + 49)/ (6b + 5)
- Tricky Math tho (Damon) - Divide. (25x^2 - 40x + 18) div. (5x - 3) need to know ...
- Algebra - 1. 2 divide by 2/3+ 3 divide by 4 divide by 4/5= 2. If 2/5 of 2/3 ...
- Algebra - Expand the expression of log5x^(1/3)y^6 5 is the base of the log. this...
- Algebra tricky ques - if w is one of the complex cube roots of unity, show that ...
- algebra - divide and simplifyr r^-7/r^-3= divide and write expression using ...
- algebra - (3x3-4x2 -x+6) Divide By (x-2) its 9three x cubed negative 4 xsquare -...
- Algebra 2 (DIVIDEPOLYNOMIALS) - How do you divide this polynomial using long ...
- Language (gerunds) - Fielding a pop fly on a sunny day can be a tricky play. I'm...

More Related Questions