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April 19, 2015

April 19, 2015

Posted by **Lucy** on Saturday, May 5, 2012 at 6:51am.

(42b^3 + 23b^2 + 38b + 49)/(6b + 5)

This is tricky..help?

- algebra ll -
**Steve**, Saturday, May 5, 2012 at 10:39ammosey on over to calc101 . com

There they have a section for polynomial long division, which shows all the intermediate steps involved.

Algebra - Divide (42b^3 + 23b^2 + 38b + 49)/ (6b + 5)

algebra ll - Divide (42b^3 + 23b^2 + 38b + 49)/ (6b + 5)

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