Posted by jhon on Saturday, May 5, 2012 at 3:09am.
You know, when you posted this earlier, with a typo, my solution should have enabled you to get the corrected answer. I assume you did that, and are now just confirming your subsequent work.
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Right?
when the water is at depth y, the radius r of the surface can be found using similar triangles:
r/y = (6.5/2)/15
r = 13/60 y
at depth y, the volume of water is
v = 1/3 pi r^2 y
= 1/3 pi (13/60)^2 y^3
= 169pi/10800 y^3
dv/dt = -12200+C = 169pi/3600 y^2 dy/dt
at y=1m=100cm, dy/dt = 21cm/min
-12200 + C = 169pi/3600 * 10000 * 21 =
C = 30971
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