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September 30, 2014

September 30, 2014

Posted by **Valerie** on Saturday, May 5, 2012 at 2:09am.

1)Mulitply:

[cosx/(1-cosx)][1+sinx/(1+sinx)]

2)Rewrite over common denominator:

[1/(1-cosx)]+[1/(1+cosx)]

3)Establish the identity:

[(1-cot^2x)/(1+cot^2x)]+1=2sin^2x

- PreCalculus (PLEASE HELP, IM BEGGING!) -
**Steve**, Saturday, May 5, 2012 at 5:03amcos/(1-cos) * ((1+sin)+sin)/(1+sin)

cos(1+2sin)/((1-cos)(1+sin))

Not sure how to make it any simpler. No chance of a typo in the problem?

----------------------------

((1+cos) + (1-cos))/(1-cos)(1+cos)

2/sin^2

----------------------

(1-cos^2/sin^2)/(1+cos^2/sin^2) + 1

(sin^2 - cos^2)/sin^2) / ((sin^2+cos^2)/sin^2) + 1

(sin^2-cos^2)/(sin^2+cos^2) + 1

(sin^2 - cos^2) + 1

sin^2 + 1-cos^2

sin^2+sin^2

2sin^2

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