Posted by **J** on Saturday, May 5, 2012 at 12:22am.

Where does the line [x, y, z] = [6, 10, 1] + t[3, 4, -1] meet the xy-plane?

- Calculus -
**MathMate**, Saturday, May 5, 2012 at 7:45am
The x-y plane is where z=0.

So solve the equation of the line where z=0, i.e.

z=1+t[-1]=0

=>

t=1

Substitute t=1 into

[x, y, z] = [6, 10, 1] + t[3, 4, -1]

gives

[x,y,z]=[6,10,1]+1[3,4,-1]=[9,14,0]

- Calculus -
**J**, Saturday, May 5, 2012 at 12:41pm
So the final answer for this one would be

[x,y,z]=[6,10,1]+1[3,4,-1]=[9,14,0] ?

Thank you!

- Calculus -
**MathMate**, Saturday, May 5, 2012 at 7:49pm
Right.

You're welcome!

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