Thursday

August 21, 2014

August 21, 2014

Posted by **Kyle** on Friday, May 4, 2012 at 9:37pm.

I solved for the intensity using Beta = (10 dB) log I/I_0

I got I to be 3.11*10^-5 W/m^2 45m away.

Then I found the energy to be 17.22*10^-11J

The answer wants it in micro joules but I'm not even sure if I've done the problem correctly.

- Physics -
**bobpursley**, Friday, May 4, 2012 at 9:45pmI dont understand the diamter being 8meters. It makes no sense.

Secondly, What is the exact question?

- Physics -
**Kyle**, Friday, May 4, 2012 at 10:24pmoh sorry the diameter is 8.4mm

and the question is asking for the

How much energy is transferred to her eardrums each second ?

- Physics -
**bobpursley**, Friday, May 4, 2012 at 11:11pm108=10 log(I/Io)

10.8=log( )

I= 10^10.8 * Io=10^10.8*1E-12=.063watts/m^2 check that.

Energy= areadrum*I= PI* .004^2*I above.

= .063watts/m^2*PI*16E-6=3.2 × 10-6 watts.

- Physics -
**bobpursley**, Friday, May 4, 2012 at 11:12pm108=10 log(I/Io)

10.8=log( )

I= 10^10.8 * Io=10^10.8*1E-12=.063watts/m^2 check that.

power= areadrum*I= PI* .004^2*I above.

= .063watts/m^2*PI*16E-6=3.2 × 10-6 joules/sec

energy in one second= 3.2E-6joules

- Physics -
**Kyle**, Friday, May 4, 2012 at 11:25pmThe range away from the stage doesn't matter?

- Physics -
**Marshall**, Monday, September 17, 2012 at 1:05amthe range doesnt matter because the relative intesity is already given in db

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