A baseball has a circumfrence of 9 in. You have a rectangular piece of leather that is 24in. x 36in. How many baseball covers can be made from assuming no loss?
You must be having an identity crisis. You've posted 5 math questions -- each with a different name.
Yes, I am having a hard time.
im hoping you can figure out my question!!!!!
This is an extremely difficult problem. I am not certain your teacher understands the difficulty of assuming no loss. The flats have to have a specific design, and cutting them from a rectangular piece of leather will entail loss.
http://www.geofhagopian.net/MAM/DesigningBaseballCover.pdf
To find out how many baseball covers can be made from the rectangular piece of leather, we need to determine the area of the leather piece and then divide it by the area of one baseball cover.
1. Start by finding the area of the rectangular leather piece:
Area = Length x Width
Area = 24 in x 36 in
Area = 864 sq. in.
2. Next, find the area of one baseball cover:
We know that the circumference of a baseball is 9 in.
The circumference of a circle is given by the formula: C = πd, where C is the circumference and d is the diameter.
Since we know the circumference (9 in), we can solve for the diameter (d):
9 in = πd
Divide both sides by π:
d = 9 in / π
d ≈ 2.87 in (approximating π to 3)
Now, the radius (r) of a circle is half of the diameter:
r = d / 2
r = 2.87 in / 2
r ≈ 1.435 in
The area of a circle is given by the formula: A = πr^2, where A is the area and r is the radius.
So, for one baseball cover:
A = π(1.435 in)^2
A ≈ 6.46 sq. in. (approximating π to 3)
3. Finally, divide the area of the rectangular leather piece by the area of one baseball cover to get the number of covers:
Number of covers = Area of leather piece / Area of one cover
Number of covers = 864 sq. in. / 6.46 sq. in. ≈ 134 covers
Therefore, assuming no loss, you could make approximately 134 baseball covers from the given rectangular piece of leather.