posted by Alex B. on .
A 6 mC charge experiences a force of 6 N directed north. What is the electric field (magnitude and direction) at the location of the charge?
Would the direction still be north? And the magnitude 1000?
E = F/q = 6/6•10^-3 =100 V/m.
The direction still be north.
magnitude of the electric field is
E = k •q /r²,
therefore, E ~ 1/r²