Posted by J on Friday, May 4, 2012 at 3:56pm.
a point on the line? Let t be any value, perhaps equal to say 1/2
then
x=6-4=2
y=-1-1=-2
z=5.5
Hi bobpursley,
I got 2 answers for a) but I'm not sure which one is correct, could you please help me determine which is correct?
the first answer I got is posted in this question, the second answer I got is this one for part a) could you please help me
for a) I got this instead:
vector equation:
[x, y, z] = [6, -1, 5] + t[-8, -2, 1]
parametric equation:
x=6+t(-2)
x=6-2t
y=-1+t(-3)
y=-1-3t
z=5+6t
and because I got this for part a), it also means my part b) changes too.. so i got this:
b) [x,y,z] = [6,-1,5] + t[-8,-2,1]
= [6,-1,5] + 1[-8,-2,1]
= [6,-1,5] + [-8,-2,1]
= 6-8, -1-2, 5+1
= (-2,-3,6)
please let me know which one is correct.. thank you!