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September 18, 2014

September 18, 2014

Posted by **J** on Friday, May 4, 2012 at 3:56pm.

b) Find another point on the line in (a).

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This is what I got for a)

r = 6i-j+5k + t(-8i-2j+k)

x = 6-8t

y = -1-2t

z = 5+t

I need help with b)

- Calculus -
**bobpursley**, Friday, May 4, 2012 at 4:14pma point on the line? Let t be any value, perhaps equal to say 1/2

then

x=6-4=2

y=-1-1=-2

z=5.5

- Calculus -
**J**, Saturday, May 5, 2012 at 12:26amHi bobpursley,

I got 2 answers for a) but I'm not sure which one is correct, could you please help me determine which is correct?

the first answer I got is posted in this question, the second answer I got is this one for part a) could you please help me

for a) I got this instead:

vector equation:

[x, y, z] = [6, -1, 5] + t[-8, -2, 1]

parametric equation:

x=6+t(-2)

x=6-2t

y=-1+t(-3)

y=-1-3t

z=5+6t

and because I got this for part a), it also means my part b) changes too.. so i got this:

b) [x,y,z] = [6,-1,5] + t[-8,-2,1]

= [6,-1,5] + 1[-8,-2,1]

= [6,-1,5] + [-8,-2,1]

= 6-8, -1-2, 5+1

= (-2,-3,6)

please let me know which one is correct.. thank you!

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