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Sketch the region enclosed by 2y=5sqrtx, y=5 and 2y+3x=8.

Decide whether to integrate with respect to x or y, and then find the area of the region.

  • calculus - ,

    Where do you get stuck?

    The curve and the sloping line intersect at (1,5/2).

    I'd integrate on y, from 5/2 to 5

    5/2 sqrt(x) - (8-3x)/2

  • Calculus - PS - ,

    Oops. Integrating on y we need x as f(y)

    4y^2/25 - (8-2y)/3

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