Posted by **ayee** on Friday, May 4, 2012 at 2:50pm.

Sketch the region enclosed by 2y=5sqrtx, y=5 and 2y+3x=8.

Decide whether to integrate with respect to x or y, and then find the area of the region.

- calculus -
**Steve**, Friday, May 4, 2012 at 3:05pm
Where do you get stuck?

The curve and the sloping line intersect at (1,5/2).

I'd integrate on y, from 5/2 to 5

5/2 sqrt(x) - (8-3x)/2

- Calculus - PS -
**Steve**, Friday, May 4, 2012 at 3:07pm
Oops. Integrating on y we need x as f(y)

4y^2/25 - (8-2y)/3

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