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November 28, 2014

November 28, 2014

Posted by **ridhi** on Friday, May 4, 2012 at 7:30am.

- maths -
**Steve**, Friday, May 4, 2012 at 12:11pma+(p-1)d = q

a+(q-1)d = p

(p-1)d-q = (q-1)d-p

[(p-1)-(q-1)]d = q-p

(p-q)d = q-p

d = (q-p)/(p-q) = -1

Tn = Tq + (n-q)d

= p + (n-q)(-1)

= p+q-n

- maths -
**ridhi**, Saturday, May 5, 2012 at 2:53amthnaks :)

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