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July 25, 2014

July 25, 2014

Posted by **stephanie** on Thursday, May 3, 2012 at 10:12pm.

- math -
**Bosnian**, Friday, May 4, 2012 at 1:49amsqrt ( x ^ 5 ) = ( x ^ 5 ) ^ ( 1 / 2 ) = x ^ ( 5 / 2 )

sqrt ( x ^ 2 ) = x = x ^ 1 = x ^ ( 2 / 2 )

1 / sqrt ( x ^ 2 ) = x ^ ( - 2 / 2 )

sqrt ( x ^ 5 ) / sqrt ( x ^ 2 ) =

sqrt ( x ^ 5 ) * 1 / sqrt ( x ^ 2 )

x ^ a * x ^ b = x ^ ( a + b )

x ^ ( 5 / 2 ) * x ^ ( - 2 / 2 ) =

x ^ [ 5 / 2 + ( - 2 / 2 ) ] =

x ^ ( 5 / 2 - 2 / 2 ) =

x ^ ( 3 / 2 ) =

sqrt ( x ^ 3 )

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