Posted by Bob on .
A 10.67 kg bowling ball has speed 4.35 m/s before hitting the floor. A(n) 66.5 g golf ball flies at much higher speed, so the two balls have exactly same kinetic energy. What is the speed of the golf ball?
Note: neglect rotation of either ball. Answer in units of m/s.
m1= 10.67 kg, v1 = 4.35 m/s, m2 = 0.0665 kg, v2 = ?
m1•v1²/2 = m2•v2²/2,
v2 = v1•sqrt(m1/m2) = 55.1 m/s.