Posted by **Anonymous** on Thursday, May 3, 2012 at 4:24pm.

binomial expansion (3a^2-2b^3)^4

is this right?

(3a^2)^4+4(3a^2)^3(-2b^3)+8(3a^2)^2(-2b^3)^2+12(3a^2)(-2b^3)^3+(-2b^3)^4

81a^8+4(27a^6)(-2b^3)+8(9a^4)(4b^6)+12(3a^2)(-8b^9)+16b^12

final answer

81a^8-216a^6b^3+288a^4b^6-288a^2b^9+16b^12

## Answer this Question

## Related Questions

- binomial expansion - how do you expand the following as a series of ascending ...
- algebra - Find 1. the binomial expansion of (3+2x)^5 simplifying terms. Hence ...
- maths - find the first 3 terms in the expansion of (x+4)(1+3x)^-2 as a series in...
- Algebra Check - What is the simplified form of 3a^4b^-2c^3? a. (81a^4c^3)/(b^2) ...
- binomial expansion - find the term containing y^3 in the expansion of (sqroot 2+...
- Binomial Expansion - Write the 6th term of the expansion of (x^2-2y)^9 and ...
- algebra - Find 1.The first 4 terms of the binomial expansion in ascending powers...
- Pre Cal. - The expression 81p^4 + 108 p^3 r^3 + 54p^2 r^6 + 12 pr^9 + r^12 is ...
- maths - in the binomial expansion of (1+x/k)^n, where k is a constant and n is a...
- Algebra2/trig - Hi, I can't figure out what I'm supposed to do on this problem. ...

More Related Questions