Posted by JD on Thursday, May 3, 2012 at 11:12am.
x-y=3 ---> x = y+3
xy = 2(x+y)
xy = 2x + 2y
y(y+3) = 2(y+3) + 2y
y^2 + 3y = 2y + 6 + 2y
y^2 - y - 6 = 0
(y-3)(y+2) = 0
y = 3 or -2, but y>0
y = 3, then x = 6
she threw a 3 and a 6
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