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December 19, 2014

December 19, 2014

Posted by **JD** on Thursday, May 3, 2012 at 11:12am.

- Algebra -
**Reiny**, Thursday, May 3, 2012 at 11:29amx-y=3 ---> x = y+3

xy = 2(x+y)

xy = 2x + 2y

y(y+3) = 2(y+3) + 2y

y^2 + 3y = 2y + 6 + 2y

y^2 - y - 6 = 0

(y-3)(y+2) = 0

y = 3 or -2, but y>0

y = 3, then x = 6

she threw a 3 and a 6

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