The grindstone weighs 80.0 kg, and has a radius of 0.320 m. The coefficient of friction between the axe and the stone is mk = 0.620 m. The radial component of the force of the axe against the grindstone is closest to...
To find the radial component of the force of the axe against the grindstone, we need to consider the gravitational force and the frictional force acting on the grindstone.
First, let's calculate the gravitational force. The weight of the grindstone is given as 80.0 kg. The formula for the gravitational force is Fg = mg, where Fg is the gravitational force, m is the mass, and g is the acceleration due to gravity. On Earth, g is approximately 9.8 m/s^2.
Substituting the values, we get Fg = (80.0 kg)(9.8 m/s^2) = 784 N.
Next, let's calculate the frictional force. The coefficient of friction between the axe and the grindstone is given as mk = 0.620. The formula for the frictional force is Ff = mkN, where Ff is the frictional force and N is the normal force. The normal force is the force exerted by the surface perpendicular to the object. In this case, it is equal to the gravitational force (Fg) acting on the grindstone.
Substituting the values, we get Ff = (0.620)(784 N) = 486.08 N (approximately).
The radial component of the force of the axe against the grindstone is equal to the frictional force (Ff). Therefore, the radial component is closest to 486.08 N.