Sunday

September 21, 2014

September 21, 2014

Posted by **Kim** on Thursday, May 3, 2012 at 2:58am.

• In the case of a linear function f (x) = ax + b, this is easy.

– If a ≠ 0, then x = −b /a.

– If a = 0, then there is no solution unless b = 0, in which case any real number is a solution.

• In the case of a quadratic function f (x) = ax^2+ b x +c, this is relatively easy.

– If a ≠ 0, then x = (-b±√(b^2-4ac))/2a

– If a = 0, then you are really in the case of a line.

Write a brief description of Newton’s method that should explain the concept to someone who knows pre-calculus, but not Calculus.

- Calculus -
**Damon**, Thursday, May 3, 2012 at 7:23amDraw a tangent to the graph of the function, see where it hits the x axis.

Then draw a new tangent to the function at the x you just found. Continue until your function is close to zero.

**Answer this Question**

**Related Questions**

Math - Can someone please explain this problem to me? I would appreciate it very...

Pure Mathematics - 1) i) use an algrbraic method to find the square root of 2+i...

Calculus - Verify the conditions for Rolle's Theorem for the function f(x)=x^2/(...

Calculus - Find the linear approximation L(x) of the given function at a, and ...

Pre Calculus - Find the roots of the function g(x)=x^3 +16x a)0,4i, -4i b)0,-4,-...

Algebra 2 - How do I solve polynomial equation by finding all complex roots? The...

Roots and Pre-cal - Find the roots of the function f(x)= x^2 +2x+2 a)-1 + sq ...

mathematics - Use the discriminant to determine the number of real roots the ...

Math - How does finding the square root of a number compare to finding the cube ...

8th grade - Can you help me find the roots of the polynominal of 5x2 - x....I ...