Posted by phil on Thursday, May 3, 2012 at 12:08am.
q1…………….<----- ------ x -->….q2
E2 P E1
E = k•q/r^2
E1 = k•q1/r1^2 = 9•10^9•50•10^-6/(0.4)^2 = 2,8•10^6 V/m,
E2 = k•q2/r2^2 = 9•10^9•30•10^-6/(0.1)^2 = 2.7•10^7 V/m,
E =E2 – E1 = 2,42•10^7 V/m.
(b)
ma =eE,
a =eE/m = 1.6•10^-19•2.42•10^7/9. 1•10^-31 =4.26•10^18 m/s².
(c)
x distance from the 50 micro coulomb)
k•q1/x²= k•q2/(0.5 –x)²
5/x² =4/(0.5–x)²
Solve for x.
(d)
k•q1/x = k•q2/(0.5 –x)
5/x =4/(0.5–x)
Solve for x
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