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August 1, 2014

August 1, 2014

Posted by **Liz** on Wednesday, May 2, 2012 at 10:18pm.

- Algebra 1 -
**Anonymous**, Wednesday, May 2, 2012 at 10:28pmmany ways to solve this: substitution, graphing, system of equations, etc.

I prefer system of equations, so here you go!

2(3x + 4y = -2) 6x + 8y = -4

3(2x - 3y = 10) -(6x - 9y = 30)subtract

17y = -34

y = -2

plug in -2 for y into one of the equations and solve...

3x + 4(-2) = -2

3x=6

x=2

- Algebra 1 -
**Reiny**, Wednesday, May 2, 2012 at 10:28pmAre we finding the intersection of these two lines ???

if so then

multiply the 1st by 3 ---> 9x + 12y = -6

multiply the 2nd by 4 ---> 8x - 12y = 40

add them

17x = 34

x = 2

plug that into the 1st

3(2) + 4y = -2

4y = -8

y = -2

x = 2, y = -2

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