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December 20, 2014

December 20, 2014

Posted by **Fred** on Wednesday, May 2, 2012 at 9:00pm.

Suppose an artist has a circular picture with a diameter 6 inches which she wishes to frame by a uniform width frame with covers 1/2 inch width uniformity of the painting and has total area equal to that of the exposed painted surface when the frame is in place.

- College Algebra/Geometry -
**bobpursley**, Wednesday, May 2, 2012 at 9:24pmIs there a question here?

- College Algebra/Geometry -
**Fred**, Wednesday, May 2, 2012 at 9:26pmWhat size should the frame be?

- College Algebra/Geometry -
**Steve**, Thursday, May 3, 2012 at 12:04amif the frame is width w, then it covers 1/2 inch of painting plus w outside the painting.

pi(3-.5)^2 = pi((3+w)^2 - (3^2-2.5^2))

25/4 = w^2 + 6w + 9 - (9-25/4)

w^2 + 6w = 0

solve that for w, and you get w=0

so, the border is just 1/2 inch wide, and does not extend outside the painting.

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