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December 21, 2014

December 21, 2014

Posted by **Kaelan** on Wednesday, May 2, 2012 at 8:19pm.

Interpret the given equation in terms of relatinve numbers of representative particles, number of moles, and masses of reactants and products.

2K(s)+2H2O(l)-->2KOH(Aq)+H2(g)

- Chemistry -
**DrBob222**, Wednesday, May 2, 2012 at 8:28pmIt look straight forward to me. I'll do one of them.

2 mols K + 2 mols H2O yield 2 mols KOH and 1 mol H2.

Now you can do the masses.

2*atomic mass K = 78 g K combine with 2*18 or 36 g H2O etc.

- Chemistry -
**Angel**, Wednesday, May 2, 2012 at 8:52pmhow many grams of solute is in 64.3 mL of 0.0238 molarity KOH?

- Chemistry -
**DrBob222**, Wednesday, May 2, 2012 at 9:03pmmols = M x L. You know M and L, solve for mols.

Then mol = grams/molar mass.

You know mols and molar mass, solve for grams.

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