Posted by carlton on Wednesday, May 2, 2012 at 7:31pm.
A rough sketch and some quick easy algebra shows that the curve intersects the lines at (2,2) and (14,4)
and the two straight lines intersect at (4,4)
so in 2 parts ....
V = π∫( x^2 - (x+2) ) dx from 2 to 4 + π∫(16 - (x+2))dx from 4 to 14
= π [(1/3)x^3 - (1/2)x^2 - 2x] from 2 to 4 + π[ 16x - (1/2)x^2 - 2x] from 4 to 14
I will let you do the arithmetic
Related Questions
calculus - Use the shell method to set up and evaluate the integral that gives ...
Calculus - Use the shell method to set up, but do not evaluate, an integral ...
calculus - 2. Let R be the region in the first quadrant bounded by the graphs of...
calculus - 2. Let R be the region in the first quadrant bounded by the graphs of...
Calculus - R is the region in the plane bounded below by the curve y=x^2 and ...
Calculus - R is the region in the plane bounded below by the curve y=x^2 and ...
Calculus - R is the region in the plane bounded below by the curve y=x^2 and ...
Calculus - Let R be the region bounded by y=x^2, x=1, and y=0. Use the shell ...
Calculus - Let R be the region bounded by y=x^2, x=1, and y=0. Use the shell ...
calculus - Use the shell method to find the volume of the solid generated by ...
For Further Reading
