Posted by quinton on Wednesday, May 2, 2012 at 7:20pm.
what is the electric field at the position 20 cm from Q2 and 60 cm from Q1?
Q2=40 micro coulombs
Q1=20 micro coulombs
Q2 and Q1 are separated by 80 cm
physics - Elena, Wednesday, May 2, 2012 at 7:27pm
60 cm or 80 cm ?????
If 80 cm =0.8 m , then
F = k•q1•q2/r² =
=9•10^9•40•10^-6•20•10^-6/0.8^2 = ...
physics - ralph, Wednesday, May 2, 2012 at 7:33pm
no elena i believe quinton is looking for the electric field positions of Q2 and Q1 separately at different distances from each respectively
physics - Elena, Wednesday, May 2, 2012 at 7:40pm
E = k•q/r^2
E1 = k•q1/r1^2 = 9•10^9•40•10^-6/(0.2)^2 =6•10^6 V/m,
E2 = k•q2/r2^2 = 9•10^9•60•10^-6/(0.6)^2 = 1.5•10^6 V/m,
E =E1 – E2 = 4.5•10^6 V/m.
physics - quinton, Wednesday, May 2, 2012 at 7:44pm
thank you very much guys..i really appreciate it.
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