Posted by **david** on Wednesday, May 2, 2012 at 5:19pm.

Write an equation for a parabola with vertex at (3,- 6) and focus at (3,- 4).

- algebra 2 -
**Henry**, Thursday, May 3, 2012 at 8:57pm
Given: V(3,-6), F(3,-4).

VF =1/4a = -4 -(-6).

1/4a = 2.

4a = 1/2.

a = 1/8.

Y = a(x-h)^2 + k.

Y = (1/8)(x-3)^2 -6.

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