Posted by david on .
Write an equation for a parabola with vertex at (3, 6) and focus at (3, 4).

algebra 2 
Henry,
Given: V(3,6), F(3,4).
VF =1/4a = 4 (6).
1/4a = 2.
4a = 1/2.
a = 1/8.
Y = a(xh)^2 + k.
Y = (1/8)(x3)^2 6.