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posted by david on Wednesday, May 2, 2012 at 5:19pm.
Write an equation for a parabola with vertex at (3,- 6) and focus at (3,- 4).
Given: V(3,-6), F(3,-4). VF =1/4a = -4 -(-6). 1/4a = 2. 4a = 1/2. a = 1/8. Y = a(x-h)^2 + k. Y = (1/8)(x-3)^2 -6.
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