Expand as a binomial series and simplify
(2x + y^3)^5
(a+b)^5 = a^5 + 5a^4b + 10 a^3b^2 + ...
you have a2x and b=y^3
(2x+y^3)^5 = (2x)^5 + 5(2x)^4(y^3) + 10(2x)^3(y^3)^2 + ...
32x^5 + 80x^4y^3 + 80x^3y^6 + ...
(2x + y^3)^5
you have a2x and b=y^3
(2x+y^3)^5 = (2x)^5 + 5(2x)^4(y^3) + 10(2x)^3(y^3)^2 + ...
32x^5 + 80x^4y^3 + 80x^3y^6 + ...