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November 26, 2014

November 26, 2014

Posted by **ali** on Wednesday, May 2, 2012 at 12:52pm.

- calcalus -
**Steve**, Wednesday, May 2, 2012 at 2:52pmwhen the water is at depth y, the radius r of the surface can be found using similar triangles:

r/y = (65/2)/15

r = 13/6 y

at depth y, the volume of water is

v = 1/3 pi r^2 y

= 1/3 pi (13/6)^2 y^3

= 169pi/108 y^3

dv/dt = -12200+C = 169pi/36 y^2 dy/dt

at y=10m=1000cm, dy/dt = 21cm/min

-12200 + C = 169pi/36 * 1000000 * 21 = 309708675

C = 309696475

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