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April 17, 2014

April 17, 2014

Posted by **ASH** on Wednesday, May 2, 2012 at 11:46am.

(tanx+1)/(secx+cscx) = sinx

- calculus -
**Steve**, Wednesday, May 2, 2012 at 12:06pmmultiply through by sec+csc to get

tan+1 = sin(sec+csc)

= sinsec + sincsc

= tan + 1

- calculus -
**Reiny**, Wednesday, May 2, 2012 at 12:07pmLS= (sinx/cosx + 1)/(1/cosx + 1/sinx)

= [(sinx + cosx)/cosx] / [ (sinx + cosx)/(sinxcosx)]

= (sinx+ cosx)/cosx * (sinxcosx)/(sinx+cosx)

= sinxcosx/cosx

= sinx

= RS

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