Post a New Question

calculus

posted by on .

Verify the identity:

(tanx+1)/(secx+cscx) = sinx

  • calculus - ,

    multiply through by sec+csc to get

    tan+1 = sin(sec+csc)
    = sinsec + sincsc
    = tan + 1

  • calculus - ,

    LS= (sinx/cosx + 1)/(1/cosx + 1/sinx)
    = [(sinx + cosx)/cosx] / [ (sinx + cosx)/(sinxcosx)]
    = (sinx+ cosx)/cosx * (sinxcosx)/(sinx+cosx)
    = sinxcosx/cosx
    = sinx
    = RS

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question