Posted by ASH on Wednesday, May 2, 2012 at 11:46am.
Verify the identity:
(tanx+1)/(secx+cscx) = sinx
calculus - Steve, Wednesday, May 2, 2012 at 12:06pm
multiply through by sec+csc to get
tan+1 = sin(sec+csc)
= sinsec + sincsc
= tan + 1
calculus - Reiny, Wednesday, May 2, 2012 at 12:07pm
LS= (sinx/cosx + 1)/(1/cosx + 1/sinx)
= [(sinx + cosx)/cosx] / [ (sinx + cosx)/(sinxcosx)]
= (sinx+ cosx)/cosx * (sinxcosx)/(sinx+cosx)
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