A group of tourists went to Sentosa. The total fare is $240. If 10 more tourists join the tour each will pay $4 less. Find the original number of tourists in the group
If there are n tourists, the cost each is 240/n
240/n - 4 = 240/(n+10)
n=20
check:
240/20 = 12
240/30 = 8 = 12-4
To find the original number of tourists in the group, we can use algebraic equations.
Let's assume that the original number of tourists in the group is 'x'.
The fare for each tourist would then be 240/x dollars.
If 10 more tourists join the group, the new total number of tourists would be x + 10.
According to the given condition, each tourist would pay $4 less, so the new fare per tourist would be (240/x) - 4 dollars.
The total fare is given as $240, so we can write the equation:
Original Fare + (Additional Tourists Fare) = Total Fare
(x * (240/x)) + (10 * ((240/x) - 4)) = 240
Now, let's simplify and solve this equation:
(240) + (10 * ((240/x) - 4)) = 240
240 + (2400/x) - 40 = 240
(2400/x) = 40
2400 = 40x
x = 2400/40
x = 60
Therefore, the original number of tourists in the group was 60.