Posted by andrew on Wednesday, May 2, 2012 at 2:35am.
(a)
Velocity in the stretched string is
v = sqrt(T/mₒ),
T = m•g,
v = sqrt(m•g/mₒ),
mₒ =m•g/v² = 3•9.8/21² = 0.067 kg/m.
(b)
v1 = sqrt(T1/mₒ) = sqrt(m1•g/mₒ) =
= sqrt(1.6•9.8/ 0.067)= 15.3 m/s.
Related Questions
physics - a stretched string is observed to vibrate with frequency 30Hz in its ...
Physics - A string is under a tension of 700.0 N. A 1.5 m length of the string ...
Physics - To demonstrate standing waves, one end of a string is attached to a ...
Physics - To demonstrate standing waves, one end of a string is attached to a ...
physics HELP! - The observed wave speed is 20.3 m/s when the suspended mass is m...
physics - Transverse waves with a speed of 50.0 m/s are to be produced on a ...
Physics repost please help - The mass of a string is 6.0 x 10^-3 kg, and it is ...
Physics - A wave on a string has a speed of 400 m/s. If the tension in the ...
Physics - A particular steel guitar string has mass per unit length of 1.79 g/m...
Physics - A string fixed at both ends is 8.71 m long and has a mass of 0.119 kg...
For Further Reading