Posted by Sarah on Tuesday, May 1, 2012 at 8:15pm.
pH = -log(H^+) = approxmately 1E-6
Solve for (H^+).
..........HX ==> H^+ + X^-
initial...0.1.....0......0
change...-x.......x......x
equil...0.1-x.....x.......x
Ka = (H^+)(X^-)/(HX)
Then dGo = -RTlnK
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