Posted by Angela on Tuesday, May 1, 2012 at 5:05pm.
If there is only one root, it occurs twice:
(x-3)(x-3) = 0
x^2 - 6x + 9 = 0
LOVE YA
The solution is x^2-6x+9=0? In ax^2 + bx + c =0 form? Can you explain please?
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