Posted by kim on Tuesday, May 1, 2012 at 2:10pm.
mols MgCl2 = grams/molar mass
M MgCl2 = mols MgCl2/L soln.
There is 1 mol Mg^2+ in 1 mol MgCl2; therefore, (Mg^2+) = (MgCl2)
There are 2 mols Cl^- in 1 mol MgCl2; therefore, (Cl^-) = 2 x (MgCl2)
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