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March 28, 2017

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Find the volume of the solid obtained by rotating the region bounded by

y=4x^2,x=1,y=0

about the x-axis.

  • cal - ,

    vol = π∫y^2 dx from 0 to 1
    = π∫16x^4 dx
    = π[(16/5)x^5] from 0 to 1
    = π(16/5 - 0] = 16π/5

  • cal - ,

    why is the intergral from 0 to 1

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