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February 7, 2016
Posted by **cjones** on Monday, April 30, 2012 at 9:24pm.

y=4x^2,x=1,y=0

about the x-axis.

- cal -
**Reiny**, Monday, April 30, 2012 at 9:33pmvol = π∫y^2 dx from 0 to 1

= π∫16x^4 dx

= π[(16/5)x^5] from 0 to 1

= π(16/5 - 0] = 16π/5

- cal -
**Anonymous**, Wednesday, May 2, 2012 at 12:23amwhy is the intergral from 0 to 1