Posted by **Anonymous** on Monday, April 30, 2012 at 9:12pm.

A bullet of mass 11.2 g is fired into an initially stationary block and comes to rest in the block. The block, of mass 1.01 kg, is subject to no horizontal external forces during the collision with the bullet. After the collision, the block is observed to move at a speed of 4.40 m/s.

(a) Find the initial speed of the bullet.

(b) How much kinetic energy is lost?

- physics -
**Elena**, Tuesday, May 1, 2012 at 8:30am
m1 =0.0112 kg, v =?

m2 = 1.01kg, u = 4.4 m/s

The law of conservation of linear momentum

m1•v + 0 = (m1+m2) •u,

(a) v =(m1+m2) •u/m1.

(b) ΔKE = m1•v^2/2 – (m1+m2) •^2/2.

## Answer this Question

## Related Questions

- physics - A bullet of mass 12.4 g is fired into an initially stationary block ...
- Physics - A bullet of mass 5.15 g is fired horizontally into a 2.74 kg wooden ...
- physics - A bullet of mass 8.0 g is fired horizontally into a 2.2 kg wooden ...
- Physics - A bullet of mass 15 g is fired with an initial speed of 287 m/s into a...
- Impulse and Momentum - A bullet of mass m is fired at speed v0 into a wooden ...
- Physics HELP! - A 20.0 g bullet is fired horizontally into a 85 g wooden block ...
- Physics- Elena please help! - A 20.0 g bullet is fired horizontally into a 85 g ...
- college physics - a bullet of mass 8g is fired into a block of mass 260g that is...
- physics - A block of wood with a mass of 1300g is sitting on a horizontal ...
- Physics - A small wooden block with mass 0.800kg is suspended from the lower end...

More Related Questions