Posted by **Anonymous** on Monday, April 30, 2012 at 7:27pm.

6% of american drivers read the newspaper while driving if 300 drivers are selected at random find the probability that between 15 and 25 say they read while driving

- Stat -
**MathGuru**, Tuesday, May 1, 2012 at 6:19pm
Mean = np = 300 * .06 = ?

Standard deviation = √npq = √(300 * .06 * .94) = ? (Note: q = 1 - p)

Once you have calculated mean and standard deviation, use z-scores to find the probability.

z = (x - mean)/sd

Find two z-scores, using 15 for x and then using 25 for x.

Once you find the z-scores, use a z-table to find the probability between the two scores.

I hope this will help get you started.

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