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6% of american drivers read the newspaper while driving if 300 drivers are selected at random find the probability that between 15 and 25 say they read while driving

  • Stat - ,

    Mean = np = 300 * .06 = ?
    Standard deviation = √npq = √(300 * .06 * .94) = ? (Note: q = 1 - p)

    Once you have calculated mean and standard deviation, use z-scores to find the probability.

    z = (x - mean)/sd

    Find two z-scores, using 15 for x and then using 25 for x.

    Once you find the z-scores, use a z-table to find the probability between the two scores.

    I hope this will help get you started.

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