Posted by opp on Monday, April 30, 2012 at 1:08am.
Thermal power is rate of thermal energy.
P = (thermal energy) / (time) = Q/t =
= m•c•ΔT / t
= (m/t) • (c) • (ΔT)
Here m/t = 4.9•10^6 kg/s
c = specific heat of water = 4186 J/kg•C
ΔT = change in the temperature = 0.50 °C
Substituting all these values in the equation we get
P = 4.9•10^6 •4186 •0.50 =
= 1.02557•10^10 W =10.2557 GW.
Ans. 0.32 •10.2557 GW = 3.28GW
Thermal power is rate of thermal energy.
P = (thermal energy) / (time) = Q/t =
= m•c•ΔT / t
= (m/t) • (c) • (ΔT)
Here m/t = 4.9•10^6 kg/s
c = specific heat of water = 4186 J/kg•C
ΔT = change in the temperature = 0.50 °C
Substituting all these values in the equation we get
P = 4.9•10^6 •4186 •0.50 =
= 1.02557•10^10 W =10.2557 GW.
Ans. 0.32 •10.2557 GW = 3.28GW
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