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September 18, 2014

September 18, 2014

Posted by **opp** on Monday, April 30, 2012 at 1:08am.

- phys -
**Elena**, Monday, April 30, 2012 at 2:06pmThermal power is rate of thermal energy.

P = (thermal energy) / (time) = Q/t =

= m•c•ΔT / t

= (m/t) • (c) • (ΔT)

Here m/t = 4.9•10^6 kg/s

c = specific heat of water = 4186 J/kg•C

ΔT = change in the temperature = 0.50 °C

Substituting all these values in the equation we get

P = 4.9•10^6 •4186 •0.50 =

= 1.02557•10^10 W =10.2557 GW.

Ans. 0.32 •10.2557 GW = 3.28GW

- phys -
**Elena**, Monday, April 30, 2012 at 3:07pmThermal power is rate of thermal energy.

P = (thermal energy) / (time) = Q/t =

= m•c•ΔT / t

= (m/t) • (c) • (ΔT)

Here m/t = 4.9•10^6 kg/s

c = specific heat of water = 4186 J/kg•C

ΔT = change in the temperature = 0.50 °C

Substituting all these values in the equation we get

P = 4.9•10^6 •4186 •0.50 =

= 1.02557•10^10 W =10.2557 GW.

Ans. 0.32 •10.2557 GW = 3.28GW

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