Sunday
April 20, 2014

Homework Help: Chemistry

Posted by Zac on Sunday, April 29, 2012 at 11:38pm.

0.200 moles of NaF are added to 1L 2.0 molar HF. The Ka = 7.2*10^-4. What is the pH?
a) 2.14
b) 6.70
c) 10.80
d) 3.00
e) 7.00

I got 4.14. pH = -log(Ka)-log([NaF]/[HF]) ==> pH = -log(7.2*10^-4)-log(.2/2) ==> pH = 4.14
Or did I do something wrong?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Chemistry - 0.200 moles of NaF are added to 1L 2.0 molar HF. What is the pH? a) ...
chemistry - The balanced reaction is CaCO3 + 2 NaF -> CaF2 + Na2CO3 If you ...
Chemistry - An unknown salt is either NaF, NaCl or NaOCl when 0.050 moles of the...
college chemistry - what is the molarity of NaF in the final solution if a ...
Chemistry - How many moles of hydrochloric acid (pKa of HF=3.14) must be added ...
chemistry - The Ksp for calcium fluoride (CaF2) is 3.9 x 10^11 at 25C. How ...
chemistry - 25 ml HCl x 1L/1000mL x .200HCl/1L = .005 mol HCl. Using the ...
General Chemistry-Acids/Bases - I'm stuck on a couple of similar problems ...
CHEMISTRY - A BUFFER SOLUTION IS MADE FORM 0.10 MOLES NaF AND 0.25 MOLES OF HF ...
Chemistry - If the solubility of CaF2 (s) in water is 5.0 x 10^-3. The ...

Search
Members