posted by Randy on .
calculate the molarity of an acetic acid solution if 39.96 mL of the solution is needed to neutralize 136mL of 1.41 M sodium hydroxide. the equation for the reaction is
HC2H3O2(aq) + NaOH(aq) > Na+(aq) + C2H3O2(aq)
mols NaOH = M x L = ?
mols acetic acid = mols NaOH (from the equation which is 1 mol NaOH = 1 mol acetic acid)
M acetic acid = mols acetic acid/L acetic acid.