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chemistry

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calculate the molarity of an acetic acid solution if 39.96 mL of the solution is needed to neutralize 136mL of 1.41 M sodium hydroxide. the equation for the reaction is
HC2H3O2(aq) + NaOH(aq) > Na+(aq) + C2H3O2(aq)
+H2O(aq)

  • chemistry -

    mols NaOH = M x L = ?
    mols acetic acid = mols NaOH (from the equation which is 1 mol NaOH = 1 mol acetic acid)
    M acetic acid = mols acetic acid/L acetic acid.

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