Posted by Confused on .
A 0.5224g sample of an unknown monoprotic acid was titrated with 0.0998M of NaOH. The equivalence point of the titration occurs at 23.82 mL. Determine the molar mass of the unknown acid.
mols NaOH = M x L = ?
mols HA = mols NaOH (since it's a monoprotic acid)
mols HA = grams HA/molar mass HA
You know mols HA and grams HA, solve for molar mass HA.