Thursday
March 30, 2017

Post a New Question

Posted by on .

A 0.5224g sample of an unknown monoprotic acid was titrated with 0.0998M of NaOH. The equivalence point of the titration occurs at 23.82 mL. Determine the molar mass of the unknown acid.

  • Chemistry - ,

    mols NaOH = M x L = ?
    mols HA = mols NaOH (since it's a monoprotic acid)
    mols HA = grams HA/molar mass HA
    You know mols HA and grams HA, solve for molar mass HA.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question