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if 180 grams of ice at -123 degrees celsius is heated to steam at 125 degrees celsius, how much energy would it take?

  • chemistry -

    So this in stages.
    q1 = heat to raise T of solid ice from -123 to solid ice at zero C.
    q1 = mass ice x specific heat ice x (Tfinal-Tinitial)
    where Tfinal = 0 and Tinitial = -123.

    q2 = heat to melt ice.
    q2 = mass ice x heat fusion.

    q3. heat to raise T of liquid water from zero C to 100 C.
    [mass water x specific heat water x (Tfinal-Tinitial)

    q4 = heat to convert liquid water at 100 C to steam at 100 C.
    q4 = [mass water x heat vaporization)

    q5 = heat to raise T of steam at 100 to steam at 125 C.
    q5 = [mass steam x specific heat steam x (Tfinal-Tinitial)]
    Total Q = sum individual q values.
    q2 =

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